Pb in PbSO4 : +2. Oxidation number of Pb is +2 PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. Add your answer and earn points. Explanation: The oxidation number of S in P b S O 4 = 6. Answer. What is the oxidation number of phosphorous in the H3PO2 molecule? Oxidation number of S=+6. Nice I mean I kinda said the answer in his question Pb +2 S-2 + H +1 2 O-1 2 → Pb +2 S +6 O-2 4 + H +1 2 O-2 . The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. Pb +2 S -2 + H +1 2 O -1 2 → Pb +2 S +6 O … Expert Answer: Let the oxidation number of Pb=x. A compound doesn't have an oxidation number, but an element in a compound does. Sum of all oxidation number =0. It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … Pb. THat leaves, though, the oxidation state of Pb to be +2. The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. D. none of these. So, SO42- can be dealt with on its own. Conversion of P b S O 4 to P b S is : A. reduction of S. B. oxidation of S. C. dissociation. Pb PbO2 PbSO4 H2O H2SO4. For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2. Within polyatomic ions, you can frequently have oxidation states that are not "normal". You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Oxidation number of O=-2. Which substance is the reducing agent in the following reaction? Since the ion has a -2 charge, the oxidation state of sulfur must be +6. H2O2 + PbS --> PbSO4 + H2O. Conversion of PbSO4 to PbS ... chemistry. Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O +1 +3 0-1 +2 +1. Thank me later Shaawana is waiting for your help. Within the sulfate ion, each oxygen does have a -2 oxidation state. H in H2 : 0. Asked by | 25th Mar, 2009, 06:56: PM. Now, since O is always -2, the S must be +6 to make the whole compound zero. How to calculate oxidation number of Pb in PbSO4?And Explain? Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) Oxidation number pbso4 Therefore, the oxidation number of S in PbSO4 is +6. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. 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